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converging (convex) lenses. The lens equation can be used to calculate the image distance for either real or virtual images and for either positive on negative lenses. The linear magnification relationship allows you to predict the size of the image. If the magnification is negative, the image is inverted.

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Ray Diagrams for Lenses. The image formed by a single lens can be located and sized with three principal rays. Examples are given for converging and diverging lenses and for the cases where the object is inside and outside the principal focal length.

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Bench Height: This value controls the height of the dragline spoil bench. Spoil Offset: This value controls the width of the dragline spoil bench. Repose Angle: When flattening a previous spoil pile for the new dragline bench, this value controls the repose angle, in degrees, of the pushed material.

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f = focal length, i = image length/height, o = object length from lens or mirror 5. DO NOT FORGET that convex mirrors are divergent and concave are convergent. That's how you use the above 4 steps to solve problems. Easy to remember because if you picture a light ray as a tennis ball you throw at a...Image size Formula Questions: 1) A lens formed an image at 30 cm, the object of 2 cm height is placed in front at 1 m. What is the size of the image? Answer: From the image size formula: hi/ho = - I/o. hi = -I/o * ho = - (30 cm / 100 cm) * 2 cm. hi = -0.15 cm. The minus sign indicates that the virtual image is inverted.

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(a) A concave mirror and a convex lens are held in water. What change, if any, do you expect to find in the focal length of either? (b) On a hot summer day in a desert, one sees the reflected image of distant parts of the sky. (This is sometimes mistaken by the observer to be the reflection of the sky in some distant lake of water.

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An arrow of 2.5 cm height is placed at a distance of 25 cm from a diverging mirror of focal length 20 cm. Find the nature, position and size of the image formed. asked Nov 3, 2017 in Class X Science by Sahil Verma ( 16 points) 10. What is the focal length of a makeup mirror that produces a magnification of 1.50 when a person’s face is 12.0 cm away? Solve with both a ray diagram and the mirror equation. (OpenStax 25.57) 0.360 m 11. A shopper standing 3.00 m from a convex security mirror sees his image with a magnification of 0.250. (a) Where is his image?

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